Question

Hey people :)
Write a *C++* program to print the ASCII code for the corresponding *string*.

Pleaseeeee Hellppp!! :')

Answer 1

Funny thing about a string... if you convert it to a series of CHARs, those can be treated as INTs.

Answer 2

i know that's what we're supposed to do, but i'm just confused about HOW to do it :(

I mean, I got perfect output in C , but c++ is just so freaking confusing :P

Answer 3

Here is an example I snagged:
//std::string s
char *a=new char[s.size()+1]
a[s.size()]=0;
memcpy(a,s.c_str(),s.size());

That is one way to do it.

Answer 4

In that, you make a char array that is the proper size to hold the string, then copy the string to it.

Answer 5

There is also strcopy.... or something like that. Let me find it.

Answer 6

And this is a nice, clean method:
http://stackoverflow.com/questions/347949/convert-stdstring-to-const-char-or-char

Pretty similar to the first I grabed.

Answer 7

Considering that C++ is a superset of C, a C solution is a C++ solution.

Answer 8

As long as you include the right things.

Answer 9

If all you must do is print the characters, you could simply create a for loop, iterate through the string and storing each index in an int and print to the screen.
However, if you'd like to get creative you can always create a class to contain your char, the ascii value, and any other property you want.

Answer 10

Hi Aaddiittii!
Here is code snippet of your "ASCII value" question:--

#include<iostream.h>
#include<conio.h>
#include<stdio.h>
void main()
{
clrscr();
int i,j,l;
char ch,str[10];
cout<<"Hi Aaddiittii! First of all, enter the length of your string:";
cin>>l;
cout<<"Enter the characters of the string sequentially & its respective ASCII code:\n";
for(i=1;i<=l;i++)
{
cin>>ch;
cout<<(int)ch<<"-";
}
getch();
}