Question

Write an equation in slope-intercept form that is perpendicular to 4x – 5y = 1 and passes through (-3, 4).
Y=mx+b
-5y=-4x+1
-y=-4/5x+1
y=4/5x-1
4=4/5(-3)+b
4=-2.4—-6.4
4=-2.4+6.4
4=4
b=6.4
m=4/5
y=4/5x+6.4
did I do this right?

Answer 1

@johnweldon1993

Answer 2

@texaschic101 @Luigi0210

Answer 3

@jdoe0001 ?

Answer 4

someone?anyone???????????????????????

Answer 5

$$
4x-5y=1 \implies -5y=-4x+1 \implies y = \cfrac{-4x+1}{-5}\\
\implies y = \cfrac{-4x}{-5}+\cfrac{1}{-5}\\\\
$$

Answer 6

ty!!!!!!!!!!!!!!

Answer 7

so, that's the slope for that one, which is PERPENDICULAR to the other one, so, the other will have a slope which is NEGATIVE RECIPROCAL to that, so pretty much just if you have a slope of say "x"

x
reciprocal of that
1/x
negativize it

-1/x

negative reciprocal

Answer 8

4x - 5y = 1
put it in slope intercept form : y = mx +b
-5y = -4x + 1
y = (-4x + 1)/-5
y = 4/5x - 1/5
slope is -5/4 (negative reciprocal for perpendicular lines.

y = -5/4x + b (sub you points in (-3,4)
4 = - 5/4(-3) + b
4 = 15/4 + b
4 - 15/4 = b
16/4 - 15/4 = b
1/4 = b

your equation would be : y = -5/4x + 1/4