Question

What is the equation in standard form of the line which passes through (1,-3) and has a slope of 2
2x-y=5
2x-y=-5
2x+y=5
2x+y=-5

Answer 1

use formula y = mx + b, you have m=2
now substitute x = 1 and y = -3
you have -3 = 2(1) + b find the value of b

Answer 2

So it's the last one

Answer 3

well you have b = -5
then you have the equation y = 2x - 5
let see which one is the same, you can switch numbers around as long as you change the sign

Answer 4

y = 2x -5
if I switch the y and the -5 then I have
5 = 2x - y

Answer 5

which is the same as 2x - y = 5

Answer 6

Can you help me with another problem please. What is the equation of the line in standard form that passes through the point (-1,4) and is parallel to the line y=2x-3

Answer 7

X-2y=6 x+2y=6 2x-y=-6 2x+y=-6

Answer 8

If it is parallel it means that the slope is the same
you have the equation y = 2x -3, the slope is 2,
since formula is y = mx + b where m = slope
do you see this?

Answer 9

So it's the last one

Answer 10

then you have the points (-1,4), to find the equation for this point substitute the x = -1 and y = 4, you need to find value of b
then you have
4 = 2(-1) + b
what is the value of b ??

Answer 11

6 just tell me the answer

Answer 12

ok you have y = 2x + 6
when you switch the y and the 6
you have
-6 = 2x -y
which is the same as 2x - y = -6