Question

cos300-sin(90-B)
---------------
cos(-B)+sin330


how would this be solved using identities

Answer 1

please anyone

Answer 2

use these :

sin(90-B) = cosB
cos(-B) = cosB
sin(-B) = -sinB
cos(x + 360) = cos(x)
sin(x + 360) = sin(x)

Answer 3

i have but i get stuck here
\[[(0.5)-cosB]/[cosb-1/2]\]

Answer 4

wonderful! one more step you're done !!

Answer 5

ONE MOAR

Answer 6

ROW ROOW ROOWW YOUR BOAT

Answer 7

GENTLY DOWWNN THE STREAM

Answer 8

lol dan

Answer 9

moral support

Answer 10

\( [(0.5)-cosB]/[cosb-1/2] \)

\(-1[cosB - 0.5]/[cosb-1/2] \)

Answer 11

is that factorisation

Answer 12

no, i just pulled -1 out

Answer 13

(a-b) = -(b-a)

Answer 14

ooh then you can cross cancel

Answer 15

exactly !

Answer 16

ooh thank you so much

Answer 17

np :)