WZ and XR are diameters. Find the measure of ZWX. I think it's 297 degrees?
@mangorox can you help?
Sorry I can't right now!
|dw:1371085212301:dw| Here CXW is an isosceles triangle. So angle CXW=CWX Subtract 144 from 180 and divide by two to find the angles at the base of traingle.
Draw the triangle CWX. Here, notice that the angle XCW of this triangle is 44 degrees. We must also notice that two sides of this triangle are the radii of this circle hence they're equal. This means that this is an isosceles triangle which means that angle CWX (which is the same angle as ZWX) will be the same as angle CXW. This will be the case since this is an isosceles triangle. So we know one angle of this triangle CWX, which is angle XCW = 44 degrees. The other two angles must be equal since this is an isosceles triangle. We know all angles of a triangle add up to 180 degrees, so the measure of each of the remaining two angles will be (180-44)/2:\[\bf \angle CWX=\angle CXW = \frac{ 180°-44° }{ 2 }=68°\]Since angle CWX = ZWX, then:\[\therefore \ \bf \angle CWX=\angle ZWX = 68°\]
@Chinese
there's only 63 here
That can't be right.
well then what would it be?
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