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OpenStudy (anonymous):
Simplify: (1+cos2x)/sin2x
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OpenStudy (primeralph):
is it cos^2(x) or cos(2x)
OpenStudy (anonymous):
@elly394 Can you answer primer's question?
OpenStudy (anonymous):
it is cos(2x)
OpenStudy (jhannybean):
@FutureMathProfessor , @bahrom7893
OpenStudy (bahrom7893):
What is Cos(2a) ?
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OpenStudy (bahrom7893):
Okay, I guess I'll answer it:
Cos(2a) = Cos(a+a) = Cos(a)Cos(a) - Sin(a)Sin(a) = Cos^2(a) - Sin^2(a)
OpenStudy (jhannybean):
Ohh!! nevermind. i did cos^(2) x -sin^(2) x
OpenStudy (bahrom7893):
We also know that 1 = Sin^2(a) + Cos^2(a), so top becomes:
Sin^2(a) + Cos^2(a) + Cos^2(a) - Sin^2(a) = 2Cos^2(a)
OpenStudy (jhannybean):
HAHAHA spoke too soon.
OpenStudy (bahrom7893):
I mean it doesn't matter if you have x or a. I wonder how my xs somehow turned into as.
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OpenStudy (bahrom7893):
And on the bottom we have: Sin(2a) = 2Sina*Cosa
OpenStudy (jhannybean):
they didn't :P
OpenStudy (jhannybean):
ohh...soyou can cancel out a cos(a)
OpenStudy (bahrom7893):
2Cos^2(a)/(2Sina*Cosa) = Cosa/Sina = Tanx
OpenStudy (bahrom7893):
I mean cotangent x
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OpenStudy (bahrom7893):
and somewhere along the way my xs became as and then xs again.
OpenStudy (jhannybean):
yesss :D
(2cos^(2) (a)) / (2 sin(a) * cos(a)) = cos (a)/sin(a) = cot(a)
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