Question

6Xsquared-41x-7
how do i factor this??

Answer 1

You can find its roots, say x1 and x2 and then write it in the form a(x-x1)(x-x2), where a is the coefficient of x^2 (6 in this case).

Answer 2

okay..

Answer 3

im somewhat confused so what would go in parenthesis, (6x-x)(x-x) what are the missing x's?

Answer 4

The roots of the quadratic. You find the discriminant and after that, you find the roots. Do you know the methodology?

Answer 5

no those words are too big

Answer 6

A quadratic is written in the form:
\[ax^2+bx+c\]
Here you have:
\[6x^2-41x-7\]
So what would be the values for a,b,c in this case?

Answer 7

\[6x ^{2}-41x-7=6x ^{2}-\left( 42-1 \right)x-7 =6x \left( x-7 \right)+1\left( x-7 \right)\]
\[=\left( x-7 \right)\left( 6x+1 \right)\]