6Xsquared-41x-7
how do i factor this??

Question

6Xsquared-41x-7
how do i factor this??

anonymous · Answer

You can find its roots, say x1 and x2 and then write it in the form a(x-x1)(x-x2), where a is the coefficient of x^2 (6 in this case).

anonymous · Answer

okay..

anonymous · Answer

im somewhat confused so what would go in parenthesis, (6x-x)(x-x) what are the missing x's?

anonymous · Answer

The roots of the quadratic. You find the discriminant and after that, you find the roots. Do you know the methodology?

anonymous · Answer

no those  words are too big

anonymous · Answer

A quadratic is written in the form:
$$ax^2+bx+c$$
Here you have:
$$6x^2-41x-7$$
So what would be the values for a,b,c in this case?

anonymous · Answer

$$6x ^{2}-41x-7=6x ^{2}-\left( 42-1 \right)x-7 =6x \left( x-7 \right)+1\left( x-7 \right)$$
$$=\left( x-7 \right)\left( 6x+1 \right)$$