solve the inequality 0 ≤ 2 − 5(x + 1) < 27
well, so, how would you solve 2 − 5(x + 1) = 27 ? well, you add this and multiply by that to the TWO sides well, in this case you do the same, but with THREE sides so, whenever you add/multiply to one, you do it to all THREE
there's only one thing you'd need to bear in mind on that, whenever you use a NEGATIVE multiplier or divider or exponential like -1 you have to "flip" the inequality sign
harobi7256 confused still?
yes
ok $$ \begin{matrix} 0 \le& 2 − 5(x + 1) &\lt 27\\ 0 \le & 2 − 5x -5 & \lt 27\\ 0 \le & − 5x -3 & \lt 27\\ \text{add 3 to isolate the "x"}\\ 3 \le& − 5x &\lt 30\\ \end{matrix} $$
now you want to solve by "x", so you just need to get rid of the pesky -5 in the middle
ok so be \[\frac{ -3 }{ 5 } \le x < -6\]
yes, you divide by -5, or multiply by -(1/5) HOWEVER as I said above, whenever you use a negative multiplier or exponential, you have to "flip" the inequality sign
okay thank you!
$$ -\cfrac{3}{5}\ge x \gt 6 $$
-6 I mean hehe $$ -\cfrac{3}{5}\ge x \gt -6 $$
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