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simplify: tan x/(secx-1)
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Multiply by \(\dfrac{\sec x+1}{\sec x+1}\) and try reducing that.
I basically just get the opposite: secx+1/tanx
Well, the instructions are kinda vague. Did you learn any half-angle identities recently? This might be an application of that.
We haven't learned those - this is part of a summer review packet and it doesn't say at all how she wants us to do it. Normally it's just using trig identities
that's good, from then, you have sec / tan + 1/tan = 1/sin + cot = csc + cot
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oh ok what @Loser66 makes sense. Thanks!
yw
It's also equal to \(\tan\left(\dfrac{x}{2}\right)\), but again, not sure if that's what the packet's looking for as an answer.
Thanks, but I think that the cscx+cotx was more what it was looking for
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