Question

solve

Answer 1

The line x -5y +10=0 bisects the join of (c,5) and (3,-4) find the value of c

Answer 2

I believe this is asking
at what point does this line cross the absolute middle of the segment
(c,5) and (3,-4)

do you know how to find the mid point of a line segment?

Answer 3

yes

Answer 4

in this case we can only find the y part of the mid point

add the two y's together and divide by 2

5 + -4 = 1, then divide by 2 = 1/2

so the y of the mid point would be .5 make sense?

Answer 5

here is our strategy for finding c.
we are going to use the line a the partial points of the line segment to find the
midpoint
once we have the mid point, of the line segment we can find the end point and c.

so if the y part of the mid point is .5, we can sub it in to x -5y +10=0
to find the x

x - 5(.5) + 10 = 0

x - 2.5 + 10 = 0

x + 7.5 = 0

x = -7.5 so the mid point of the line segment is (.5, -7.5)

we know this, because the line can only cross the line segment at one point, and they tell us, that it is the bisector.

Answer 6

so do you know how to find an end point when you have a midpt and 1 endpt?

Answer 7

so, what to do next

Answer 8

sorry I wrote the mid wrong above, I reversed it

it should be (-7.5, .5)

mult the mid point by 2 and subtract the end we know

2* (-7.5, .5 ) = ( -15, 1)

- (3, -4)
--------
( 12, 5) is the end point

c = 12

Answer 9

make sense?

Answer 10

how ur end point came,
-15,1
and 3, -4

Answer 11

to find mid point, you add the ends and divide by 2

when you have a mid and a end you take the mid *2 and then subtract the end you know

Answer 12

i didn't understand this step
mult the mid point by 2 and subtract the end we know

2* (-7.5, .5 ) = ( -15, 1)

- (3, -4)
--------
( 12, 5) is the end point

c = 12

Answer 13

sorry, you are right there is an error,,,duh

-15 - 3 = -18

the point should be (-18, 5)

c = -18 my bad

(-18, 5)
+ (3, -4)
--------
-15, 1

(-15/2, 1/2) = mid

(-7.5, .5)

Answer 14

apologies

Answer 15

i m not understanding how your
-15 - 3 = -18
came
plse help me to understand ths

Answer 16

you don't understand that

-15 -3 is the same as -15 + (-3) = -18 or is it something else?

Answer 17

mid point of (c,5) & (3,-4) is \[\left( \frac{ c+3 }{ 2 },\frac{ 1 }{ 2 } \right)\]
Because it lies on line x-5y+10=0
\[\frac{ c+3 }{ 2 }-5*\frac{ 1 }{ 2 }+10=0\]
or c+3-5+20=0
c+18=0
c=-18