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4. There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition? 70 1,680 40,320
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choose begins with a C
C(8,4)
what?
oh
So 70 ways
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That's right.
\[_{8}P _{4}=\frac{ 8! }{ 4! }=1680\]
Maybe it's that you guys just haven't had coffee, but this answered could not be more wrong. Obviously the coach could not select the same team twice why would he ? So the answer is not a combination , its permutation problem , and the answer is 1680
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