Question

Question 2 (Multiple Choice Worth 4 points)

(06.05 MC)

The coordinates of the vertices of quadrilateral ABCD are A(6, 7), B(4, 2), C(1, 5), and D(3, 8).

ABCD is reflected across the x-axis to form PQRS. What is the length of diagonal PR?

ANSWER IN SQUARE UNITS
HELP PLEASE

Answer 1

all you need is the point a and the point c

Answer 2

diagonal of ac = length of diag of pr

Answer 3

Okay then how do I set up a problem?

Answer 4

h^2 = a^2 + b^2

Answer 5

okay so I..
do 6/5?

Answer 6

A (6, 7), C (1, 5)
x1, y1 x2, y2

Answer 7

is this x1+y1= x2+x1

Answer 8

ooh wait I have that wrong, I'm sorry but i'm so clueless about geometry

Answer 9

h^2 = a^2 + b^2
a = x2 - x1
b = y2 - y1

Answer 10

okay and you do A/b?

Answer 11

all good dude

Answer 12

A/b...?

Answer 13

too bad I can't jus have you take my whole exam so I won't have to worry about geometry anymore:/

Answer 14

like hold on let me get the answer possibilities

Answer 15

pythag theorum concerning right angled triangles

\[h^2 = a^2 + b^2\]

Answer 16

squared 37 units

squared 19 units

squared 82 units

squared 29 units

Answer 17

ok, now pick your answer

Answer 18

h2= a2+b2

so h2= (4-6)2+ (2-7)2

Answer 19

almost... where did u get the 4 and the 2 from tho...?

Answer 20

x2 and y2?

Answer 21

for the point C... what are the coordinates for C?

Answer 22

(1,5)

Answer 23

so x2 is 1
and y2 is 5

Answer 24

(x, y)
(1, 5)

Answer 25

so h2= ( x2 -6)2+ ( y2 -7)2

Answer 26

h2= 41?

Answer 27

no.
if h2= ( x2 -6)2+ ( y2 -7)2
and x2 = 1
and y2 = 5
...show me ur eqns so i can spot error

Answer 28

I showed you everything I have? I'm so lost that's why I asked for help.

Answer 29

ooh wait i see my error