Question

Find the area of the plane domain bounded by the curves

Answer 1

\[y=\sqrt[3]{x^2} \] , \[y=\frac{ 1 }{ 4+x^2 }\] , x=2 , \[x=2\sqrt{3}\]

Answer 2

It can be calculated by this integral :
\[\Large I=\int_2^{2\sqrt3}\left|\sqrt[3]x^2-\frac1{4+x^2}\right|~\mathrm dx\]