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Simplify (3ab^7)^2. @jim_thompson5910
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square each term
and use the idea that (a^b)^c = a^(b*c)
We have : \[(3ab^7)^2=3^2a^2\left(b^7\right)^2=3^2a^2b^{7\times2}=3^2a^2b^{14}\]
I have two options that look like yours, @Noura11 but instead of a 3 at the front, it's a 6 or a 9.
3^2 is out front, not just 3
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3^2=3*3=9
Oops >.< Thanks guys.
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