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Mathematics 8 Online
OpenStudy (math2400):

Find the limit as x c approaches -2 from the left. Should I use l'hopital's rule? ***Posting problem!

OpenStudy (math2400):

OpenStudy (math2400):

*as c not x. typo!

OpenStudy (yrelhan4):

l hospital isnt really necessary here. i am not really able to understand what c is?

OpenStudy (yrelhan4):

x--> -2 is that right?

OpenStudy (math2400):

yes

OpenStudy (yrelhan4):

ok so.. as it approaches from the left hand side of -2.. so the mod will result in a negative value.. so you can cancel |x+2|/(x+2) to give -1..

OpenStudy (yrelhan4):

now you have -(x+3).. put in -2 here.. -(-2+3) = -1..

OpenStudy (yrelhan4):

yeah?

OpenStudy (math2400):

so the absolute value does not make a diff? like i can just cancel it? i was thinking i had to do something with that absolute value...but that's it then?

OpenStudy (yrelhan4):

as i said.. it would result in a negative value.. so you will open it as -(x+2).. so cancelling the numerator and the denominator will give you -1..

OpenStudy (math2400):

ohhh got u! so if we were approaching it from the right u'd get a pos value which would be 1 then

OpenStudy (yrelhan4):

absolutely.. :)

OpenStudy (math2400):

sounds good! im always tryin to make my problems harder than they are ahah thank yoU!

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