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Mathematics
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Fourier series
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I need find the Fourier Cosine series of f(x) = x for x in [0, π]
what is this ? sawtooth function?
I find \[a_{n}=π/2\]
use integration by parts.
and \[a_{n}=\frac{ 2*(-1)^n-2 }{ π*n^2 }\]
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take 2 common, you see that for even values, a_n disappears
just put your series for odd values.
Yes but are my calculations for a.0 and a.n correct?
do you have mathematica?
a_0 seems to be correct
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Because when I plot it. It seems not correct
put x=0 and see if you can get this or not http://www.wolframalpha.com/input/?i=Sum%5B1%2F%282n%2B1%29%5E2%2C+%7Bn%2C+0%2C+Infinity%7D%5D
seems correct ... just get rid of that -1^n thing ... you only have odd terms. |dw:1371302123706:dw|
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