Question

Solve For X, If There Are Multiple Answers Use a Comma To Separate Your Answers.

Answer 1

I got 0 and 7

Answer 2

@PatrickJordon
Cross Multiply & expand them.
Then take everything on Left Hand Side . This will give u a Quadratic equation to solve . Since u have tried already See the attachment

Answer 3

3,5,-.64 ?

Answer 4

The Decimal number does not seem correct to me :/

Answer 5

I made a mistake .. it should be -3x in place of -3 .. Sorry 4 that

Answer 6

hmmm, I get 0 and 7 as well :/

Answer 7

Its ok @Anu2401 every one makes a slight mistake :)

Answer 8

$$
\cfrac{2x+x^2-3x}{x-6}=\cfrac{6x}{2x-6} \implies
\cfrac{x^2-7x}{2x-6}=0\\
\implies
x(x-7)=0

Answer 9

err

Answer 10

$$
\cfrac{2x+x^2-3x}{x-6}=\cfrac{6x}{2x-6} \implies
\cfrac{x^2-7x}{2x-6}=0\\
\implies
x(x-7)=0
$$

Answer 11

hehe

Answer 12

@PatrickJordon
Here is the corrected one

Answer 13

hmm, a typo :/

Answer 14

$$
\cfrac{2x+x^2-3x}{2x-6}=\cfrac{6x}{2x-6} \implies
\cfrac{x^2-7x}{2x-6}=0\\
\implies
x(x-7)=0
$$

Answer 15

@jdoe0001 we were partly there and @Anu2401 thanks alot :)

Answer 16

@jdoe0001 @PatrickJordon
Just one little thing . in this case cancelling out the common term will result in losing a solution. There is one more along with 0,7 . It is 3

Answer 17

:) gottcha thnx