Question

x^2+3x/(9-x^2)

Answer 1

You have written \(x^{2} + \dfrac{3x}{9-x^{2}}\). Is that what you intended?

Plus, you provided no problem statement.

Answer 2

x^2+3x/(9-x^2)
x(x+3) /(x+3)(x-3)
factor numerator and denominator

can u do that?

Answer 3

i believe @Jay567 want us to simplify it

Answer 4

I used this formula a^2 - b^2 =(a+b)(a-b)

Answer 5

Do you know how to factor?

Answer 6

I'm trying to simplify it, yes. I got until this part: -x/x+3 @Zale101 That gets you X^2-9 not 9-X^2.

Answer 7

\[(x^2+3x)/(9-x^2)\]

Answer 8

You can factor the denominator as @Zale101 pointed out, if you use \(a^2=9\) and \(b^2=x^2\)

Answer 9

You can also factor an 'x' out of your numerator.