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(x)=3x g(x)=-2x^2-2x Find (f-g)(x)
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so for this how do I start?@jim_thompson5910
any ideas? @dan815
u just need to subtract the functions
so -2x^2-2x-3x?
so -2x^2-5x?
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other way
its f-g
oh so 3x--2x^2-2x
ya
simplify it
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so 3x+2x^2-2x 2x^2+x
yep good
ty!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
what????@Jhannybean is 2x^2+x wrong?
now im confuse, i need @jim_thompson5910 he's a pro at these
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(3x) - (-2x^2-2x)
(3x) - (-2x^2-2x)=2x^2+5x right?
Actually,this is what i got. \[f(x) = 3x \]\[g(x) = -2x^2-2x\]\[(f-g)(x)\]\[\large 3x - [-2x^2 - 2x]\]\[3x + 2x^2 + 2x \]\[2x^2 + 5x\]
i believe so
yep, you're right xD
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you did it wrong the first time, you got \(2x^2 +x \) as your answer.
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