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Mathematics 10 Online
OpenStudy (anonymous):

(x)=3x g(x)=-2x^2-2x Find (f-g)(x)

OpenStudy (anonymous):

so for this how do I start?@jim_thompson5910

OpenStudy (anonymous):

any ideas? @dan815

OpenStudy (dan815):

u just need to subtract the functions

OpenStudy (anonymous):

so -2x^2-2x-3x?

OpenStudy (anonymous):

so -2x^2-5x?

OpenStudy (dan815):

other way

OpenStudy (dan815):

its f-g

OpenStudy (anonymous):

oh so 3x--2x^2-2x

OpenStudy (dan815):

ya

OpenStudy (dan815):

simplify it

OpenStudy (anonymous):

so 3x+2x^2-2x 2x^2+x

OpenStudy (dan815):

yep good

OpenStudy (anonymous):

ty!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

what????@Jhannybean is 2x^2+x wrong?

OpenStudy (anonymous):

now im confuse, i need @jim_thompson5910 he's a pro at these

OpenStudy (bahrom7893):

(3x) - (-2x^2-2x)

OpenStudy (anonymous):

(3x) - (-2x^2-2x)=2x^2+5x right?

OpenStudy (jhannybean):

Actually,this is what i got. \[f(x) = 3x \]\[g(x) = -2x^2-2x\]\[(f-g)(x)\]\[\large 3x - [-2x^2 - 2x]\]\[3x + 2x^2 + 2x \]\[2x^2 + 5x\]

OpenStudy (bahrom7893):

i believe so

OpenStudy (jhannybean):

yep, you're right xD

OpenStudy (jhannybean):

you did it wrong the first time, you got \(2x^2 +x \) as your answer.

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