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Mathematics 13 Online
OpenStudy (dan815):

y'=(y/x) -y^2 Solving using substitution method

OpenStudy (anonymous):

Hmm... \(y'\) is not a function of \(y/x\) though. This isn't homogeneous, is it?

OpenStudy (anonymous):

This will be a weird substitution :/

OpenStudy (dan815):

yeah!

OpenStudy (anonymous):

Oi I remember doing these in Calc I

OpenStudy (jhannybean):

LOL im heading out. Ill be back in a bit

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