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Mathematics 17 Online
OpenStudy (anonymous):

ANYBODY HELP !!!!!!

OpenStudy (anonymous):

OpenStudy (whpalmer4):

Which problem do you need help solving?

OpenStudy (anonymous):

any

OpenStudy (whpalmer4):

Okay, let's do the first one. |dw:1371431326484:dw| a. Find the length of side b to two decimal places. b. Find the length of side a to two decimal places in three different ways. Any idea how to tackle this?

OpenStudy (anonymous):

yeah im sorry i knew that one. Can you help with the second one?

OpenStudy (whpalmer4):

Okay, fine. Can you find the circumference of that circle? The angle can be found by this proportion: \[\frac{15}{C} = \frac{\theta}{360}\] if \(C\) is the circumference.

OpenStudy (anonymous):

5400/Ctheta?

OpenStudy (anonymous):

i have till ten to get points!AHHHH

OpenStudy (mertsj):

C = 12 pi Replace C with 12 pi. Multiply 15x360 and then divide by 12 pi. That will be the angle theta

OpenStudy (anonymous):

theta = 450

OpenStudy (whpalmer4):

Isn't all the way around the circle only 360 degrees? :-)

OpenStudy (mertsj):

Seems too big since the entire circle would only be 360 degrees.

OpenStudy (whpalmer4):

You forgot to divide by pi = 3.14...

OpenStudy (anonymous):

oops sorry forgot the pi sign ooops

OpenStudy (whpalmer4):

always look at your results with a questioning eye and ask yourself if they make sense.

OpenStudy (anonymous):

143.3121019

OpenStudy (anonymous):

which problem are you doing?

OpenStudy (whpalmer4):

That's more like it...although not exactly what I got, and the problem does ask for the nearest 100th...

OpenStudy (whpalmer4):

this is the 2nd problem

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

143.31

OpenStudy (whpalmer4):

What are you using for the value of pi?

OpenStudy (anonymous):

calculator pi

OpenStudy (whpalmer4):

Interesting. I get 143.239 using 3.1415926535

OpenStudy (anonymous):

but 15 times 360 = 5400 12 times 3.14 = 37.68 5400/37.68=143.31

OpenStudy (whpalmer4):

http://www.wolframalpha.com/input/?i=15*360%2F(12*pi) Ah, but you are using 3.14, and those extra digits can make a difference, obviously.

OpenStudy (anonymous):

okay well my calculator must stop at 3.14 cuz i get the same thing using calculator pi

OpenStudy (whpalmer4):

Maybe it does. But here, punch in some extra digits and have a better chance of getting the right answer: pi = 3.141592

OpenStudy (whpalmer4):

I'd hate to see you do the work correctly but get marked off just because your answer didn't round to the right digit in the 100ths place!

OpenStudy (anonymous):

143.2394786

OpenStudy (whpalmer4):

Right, now round that to the nearest 100th of a degree, as requested by the problem statement.

OpenStudy (anonymous):

143.24

OpenStudy (whpalmer4):

Yep, I believe that to be a true and correct answer for problem #2. Shall we try #3?

OpenStudy (anonymous):

yes!

OpenStudy (whpalmer4):

Great! I like sine curves :-)

OpenStudy (whpalmer4):

You can draw nearly anything with the right combination of them! \[y=-\sin(x-\frac{\pi}{4}) + 2\]

OpenStudy (whpalmer4):

Let's do the easy part first. What does adding +2 to the function do to the graph?

OpenStudy (whpalmer4):

adding +2 to the result of the function, that is

OpenStudy (whpalmer4):

if we've got \(y = \sin x\) and we change it to \(y = \sin x + 2\) what happens?

OpenStudy (anonymous):

my calculator is being stupid. should it move 2 spaces to the left?

OpenStudy (anonymous):

@whpalmer4

OpenStudy (whpalmer4):

Here, I'll be your human calculator :-) x y = sin x y = sin x + 2 0 0 2 pi/2 1 3 pi 0 2 3pi/2 -1 1 2pi 0 2 etc.

OpenStudy (anonymous):

so it moves by 2 each time

OpenStudy (whpalmer4):

OpenStudy (anonymous):

ok i got it now

OpenStudy (whpalmer4):

gives us a vertical translation of 2

OpenStudy (whpalmer4):

if we had subtracted 3 instead of adding 2, we'd have a vertical translation of -3.

OpenStudy (anonymous):

okay!

OpenStudy (whpalmer4):

Next, let's tackle amplitude. Amplitude is just the vertical scale of the function. Normally, the amplitude of the sine function is 1, because starting at y = 0, it goes to y = 1 and y = -1 as its most extreme values. written more precisely, if you have a function \(y = a \sin x\), the amplitude is given by \(|a|\).

OpenStudy (whpalmer4):

So what is the amplitude of \(y = -\sin(x-\frac{\pi}{4})+2\) ?

OpenStudy (whpalmer4):

It might be helpful to remember that \( -\sin x = -1\sin x\)

OpenStudy (anonymous):

1

OpenStudy (whpalmer4):

right!

OpenStudy (anonymous):

:)

OpenStudy (whpalmer4):

okay, we've done amplitude, we've done vert. translation, that leaves period and phase shift, which are trickier to grasp for many people (myself included). maybe you'll be an exception :-)

OpenStudy (whpalmer4):

you know, before we do that, let's do the vertical translation and amplitude for the other half of the problem. \(y = 2 \cos 2\pi x\) what is the amplitude, and what is the vertical translation?

OpenStudy (anonymous):

amplitude is 1 and vertical translation is 2

OpenStudy (whpalmer4):

How did you arrive at those answers?

OpenStudy (whpalmer4):

Oh, those are correct for the 1st equation, yes. How about the second equation, \(y = 2 \cos 2\pi x\) ?

OpenStudy (anonymous):

oh oops sorry i though t you were asking what we already did above! Sorry!

OpenStudy (whpalmer4):

No problem.

OpenStudy (whpalmer4):

It would be a problem if you thought those were the answers for the second equation, however :-)

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

would it be zero?

OpenStudy (whpalmer4):

So, what do you think the corresponding answers for the equation \(y = 2\cos 2 \pi x\) are?

OpenStudy (whpalmer4):

for amplitude, or vertical translation?

OpenStudy (anonymous):

vertical translation?

OpenStudy (whpalmer4):

is that an answer, or a prayer? :-)

OpenStudy (anonymous):

a prayer lol

OpenStudy (whpalmer4):

(my old math teacher loved that line, and so do I!)

OpenStudy (whpalmer4):

vertical translation of 0 is correct.

OpenStudy (anonymous):

lol its awesome! and im right?

OpenStudy (whpalmer4):

FWIW, my goal is always to make anyone I help understand well enough that they answer with confidence.

OpenStudy (whpalmer4):

yes, you are correct, vertical translation is 0. how about amplitude?

OpenStudy (anonymous):

okay um hold on

OpenStudy (anonymous):

is it 2?

OpenStudy (whpalmer4):

yes? ;-)

OpenStudy (anonymous):

what?

OpenStudy (whpalmer4):

yes, the answer is 2. I was hoping you were certain about it :-)

OpenStudy (anonymous):

lol :) yay im right!

OpenStudy (whpalmer4):

great. now for the tricky stuff. sorry, the really, really, really easy stuff :-)

OpenStudy (anonymous):

lol

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