ANYBODY HELP !!!!!!
Which problem do you need help solving?
any
Okay, let's do the first one. |dw:1371431326484:dw| a. Find the length of side b to two decimal places. b. Find the length of side a to two decimal places in three different ways. Any idea how to tackle this?
yeah im sorry i knew that one. Can you help with the second one?
Okay, fine. Can you find the circumference of that circle? The angle can be found by this proportion: \[\frac{15}{C} = \frac{\theta}{360}\] if \(C\) is the circumference.
5400/Ctheta?
i have till ten to get points!AHHHH
C = 12 pi Replace C with 12 pi. Multiply 15x360 and then divide by 12 pi. That will be the angle theta
theta = 450
Isn't all the way around the circle only 360 degrees? :-)
Seems too big since the entire circle would only be 360 degrees.
You forgot to divide by pi = 3.14...
oops sorry forgot the pi sign ooops
always look at your results with a questioning eye and ask yourself if they make sense.
143.3121019
which problem are you doing?
That's more like it...although not exactly what I got, and the problem does ask for the nearest 100th...
this is the 2nd problem
oh
143.31
What are you using for the value of pi?
calculator pi
Interesting. I get 143.239 using 3.1415926535
but 15 times 360 = 5400 12 times 3.14 = 37.68 5400/37.68=143.31
http://www.wolframalpha.com/input/?i=15*360%2F(12*pi) Ah, but you are using 3.14, and those extra digits can make a difference, obviously.
okay well my calculator must stop at 3.14 cuz i get the same thing using calculator pi
Maybe it does. But here, punch in some extra digits and have a better chance of getting the right answer: pi = 3.141592
I'd hate to see you do the work correctly but get marked off just because your answer didn't round to the right digit in the 100ths place!
143.2394786
Right, now round that to the nearest 100th of a degree, as requested by the problem statement.
143.24
Yep, I believe that to be a true and correct answer for problem #2. Shall we try #3?
yes!
Great! I like sine curves :-)
You can draw nearly anything with the right combination of them! \[y=-\sin(x-\frac{\pi}{4}) + 2\]
Let's do the easy part first. What does adding +2 to the function do to the graph?
adding +2 to the result of the function, that is
if we've got \(y = \sin x\) and we change it to \(y = \sin x + 2\) what happens?
my calculator is being stupid. should it move 2 spaces to the left?
@whpalmer4
Here, I'll be your human calculator :-) x y = sin x y = sin x + 2 0 0 2 pi/2 1 3 pi 0 2 3pi/2 -1 1 2pi 0 2 etc.
so it moves by 2 each time
ok i got it now
gives us a vertical translation of 2
if we had subtracted 3 instead of adding 2, we'd have a vertical translation of -3.
okay!
Next, let's tackle amplitude. Amplitude is just the vertical scale of the function. Normally, the amplitude of the sine function is 1, because starting at y = 0, it goes to y = 1 and y = -1 as its most extreme values. written more precisely, if you have a function \(y = a \sin x\), the amplitude is given by \(|a|\).
So what is the amplitude of \(y = -\sin(x-\frac{\pi}{4})+2\) ?
It might be helpful to remember that \( -\sin x = -1\sin x\)
1
right!
:)
okay, we've done amplitude, we've done vert. translation, that leaves period and phase shift, which are trickier to grasp for many people (myself included). maybe you'll be an exception :-)
you know, before we do that, let's do the vertical translation and amplitude for the other half of the problem. \(y = 2 \cos 2\pi x\) what is the amplitude, and what is the vertical translation?
amplitude is 1 and vertical translation is 2
How did you arrive at those answers?
Oh, those are correct for the 1st equation, yes. How about the second equation, \(y = 2 \cos 2\pi x\) ?
oh oops sorry i though t you were asking what we already did above! Sorry!
No problem.
It would be a problem if you thought those were the answers for the second equation, however :-)
lol
would it be zero?
So, what do you think the corresponding answers for the equation \(y = 2\cos 2 \pi x\) are?
for amplitude, or vertical translation?
vertical translation?
is that an answer, or a prayer? :-)
a prayer lol
(my old math teacher loved that line, and so do I!)
vertical translation of 0 is correct.
lol its awesome! and im right?
FWIW, my goal is always to make anyone I help understand well enough that they answer with confidence.
yes, you are correct, vertical translation is 0. how about amplitude?
okay um hold on
is it 2?
yes? ;-)
what?
yes, the answer is 2. I was hoping you were certain about it :-)
lol :) yay im right!
great. now for the tricky stuff. sorry, the really, really, really easy stuff :-)
lol
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