WHAT IS THE VERTEX OF THE PARABOLA DESCRIBED BY Y=X^2-12X+3

Question

jdoe0001 · Answer

so yo have the so-called standard equation form you'd need to change it to the VERTEX form http://tccl.rit.albany.edu/knilt/images/1/12/Standard-vertex-forms.png

jdoe0001 · Answer

so, do you know what a perfect square trinomial is?

anonymous · Answer

NO MY TEACHER DIDNT SAY ANY THING ABOUT THAT

johnweldon1993 · Answer

Well the 'x' coordinate can be found by using the equation

$$-\frac{ b }{ 2a }$$

you have an equation in standard form

ax² + bx + c
x² -12x + 3

so

a = 1
b = -12
c = 3

Plug them into that equation

$$\frac{ 12 }{ 2 }$$

Now you can see the vertex 'x' coordinate = 6

To find the 'y' coordinate....plug (6) in for 'x' of your original equation

Y = x² - 12x + 3
Y = 6² - 12(6) + 3
Y = ...?

anonymous · Answer

SO MY ANSWER IS (6,-33)

johnweldon1993 · Answer

That would be correct...those are the coordinates of the vertex

johnweldon1993 · Answer

And I hope you see how I did it and it is clear :)

anonymous · Answer

THANK YOU I WQROTE DOWN THE WHOLE THING IN MY NOTES TO HAVE FOR MY OTHER PROBLEMS

johnweldon1993 · Answer

Perfect! :) and you're welcome!