It takes Andy 0.50 seconds to lift a 98-newton box from the floor and place it on the table. If he expends a constant power of 137 watts during this time, what is the height of the table?

My LAST question! Anyone willing to help me out?

Question

It takes Andy 0.50 seconds to lift a 98-newton box from the floor and place it on the table. If he expends a constant power of 137 watts during this time, what is the height of the table?

My LAST question! Anyone willing to help me out?

anonymous · Answer

calculate the total work done first.

anonymous · Answer

since you have the time taken and the average power, you can calculate the work done in bringing the 98 Newton box from ground to a heigh H

anonymous · Answer

So is there a formula for it? Sorry, science isnt my thing.

anonymous · Answer

ok i'll help you find the work done.

You have 137 watts. 137watts = 137 joules of energy expanded PER second .

anonymous · Answer

so using the formula Power x Time = work done. so 137 x 0.5 =68.5 Joules of energy used to bring the mass to heigh H

anonymous · Answer

now using Force x distance = work done, 98 x H = 68.5 J

anonymous · Answer

H = 68.5/98

anonymous · Answer

I understood it! :D Yay! Thank you. So this wasnt just a one equation problem. you had to find the work done. No wonder i didnt get it. Thank you sooooo much :)

anonymous · Answer

yeap, correct. =)

anonymous · Answer

Really appreciate the help :)