Question

Approximate the real number solutions to the polynomial function f(x) = x3 + 4x2 – 4x – 16 .

Answer 1

at least 1

Answer 2

at most 3

Answer 3

huh ?
@Jhannybean help ?

Answer 4

remember our last problem? the number of zeroes is determined by the variable with the highest power in a polynomial? What he's saying it you can have AT MOST 3 zeroes of a function (\(\large \color{green}{x^3}+4x^2-4x+16\)) and can have AT LEAST 1 after you break it down to the factored form.

Answer 5

i suggest grouping

Answer 6

but this questions is kind of different, thats why im confused.

Answer 7

i dont get what to do.

Answer 8

@completeidiot is better at factoring this than i am :) haha. still learning.

Answer 9

factor x^3+4x^2

also factor -4x-16

Answer 10

-4(x+4)
im confused.

Answer 11

f(x)=x^3+4x^2-4x-16=x^2(x+4)-4(x+4)=(x+4)(x^2-4)=(x+4)(x-2)(x+2)=0
so x=-4, x=2, x=-2

Answer 12

thankkyyoooouuuu !!!