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so steps using zero property solve this equation pls: y^3=-22y^2-40y
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First step is to move everything to the left side of your equation. What would you get?
You can do this by adding +22y^2 +40y to both sides.
if i subtract y^3 i get 0=-23y-40y right
You would subtract y^3 from both sides then, but it's easier to make everything positive than keep it negative.
so what i get after subtract y^3
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-y^3 + y^3 = -y^3 -22y^2 -40y What would this simplify to?
but y^3 is not a square root how do i solve for y?
Follow me on this. It'll make sense one we work it step by step. Did you simplify the expression i presented in my last post?
simply ?
so i devided by y
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?
dividing by y will not help us. |dw:1371602242866:dw|
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