Help simplifying:
\[\frac{ 2x^3+4x^2+10x+4 }{ x^3+3x^2+5x+3 }\]
|dw:1371606643029:dw| Does it make sense now? (Btw, this isn't in simpliest form. You know what to do next?
\[\large \large \large \large \large \frac{ 2x^3 }{ x^3 } + \frac{ 4x^2 }{ 3x^2 } + \frac{ 10x }{ 5x } + \frac{ 4 }{ 3 }\] ^Just to make it neater. >_> So you know what to do next?
2+1+2+4/3?
^How did you get that?
I don't think I'm getting it
Do you understand how I split it into 4 monomials?
Yes. What's 2x^3/x^3? Doesn't the x^3 cancel out?
Well. x^3 divided by x^3 cancel out. 2 is still there. So it would be 2. Now what's 4x^2 divided by 3x^2?
1?
I mean x^2
Remember. We're dividing. x^2 divided by x^2 cancel out. We're left with: \[\large \large \frac{ 4 }{ 3 } OR 1.33\]
What would the next monomial simplify to?
Okay. 2
Correct!!! What's the next one?
Just 4/3
So the answer is 2+4/3+2+4/3?
No.
You remember each simplify monomial gives you, right? You basically add up all of them. (Since they're all like terms) What would that give you?
12/6 2
It should give you: 2 + (4/3) + 2 + (4/3) What does that simplify to? Well 2 + 2 is 4. (4/3) + (4/3) = (8/3) or (2.66) So your answer is either 20/3 or 6.66 How did I get 20/3? Well, 4 can be written as (4/1) To add (4/1) to (8/3), you want to find the least common denominator. I can multiply (4/1) by 3 to get (12/3). (12/3) and (8/3) has a common denominator. The final step to add both fraction is to add the numerator, but keep the denominator. This will give you 20/3. I hope this help!
Ah. Thank you so much!
No problem. :) As long as you understand it, those problem would be quite easy for you. Just keep on practicing. :)
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