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Show that tan15 degrees = 2 - sqrt(3) by using the double angle formula.
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\[\tan 15=2-\sqrt{3}\] by using double angles
I think that's the wrong formula — you want the half angle formula. \[\tan^2 u = \frac{1-\cos(2u)}{1+\cos(2u)}\] \[\tan u = \sqrt{ \frac{1-\cos(2u)}{1+\cos(2u)}}\]You know the value of \(\cos(2u)\) if \(u=15\)...
\[\tan15= \tan(45-30)\] expand that
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