Question

ageag

Answer 1

well then (x-1) is a factor of f(x)...because 1 makes f equal to zero\[f(x)=(x-1)g(x)\]\[f(1)=(1-1)g(1)=0\times g(1)=0\]makes sense?

Answer 2

$$f(1)=0\implies f(x)=(x-1)g(x)$$this is the factor theorem

Answer 3

http://en.wikipedia.org/wiki/Factor_theorem

Answer 4

I figured it out, but thank you.