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Mathematics 11 Online
OpenStudy (anonymous):

iS THIS CORRECT???

OpenStudy (anonymous):

OpenStudy (anonymous):

iS IT CORRECT???^

mathslover (mathslover):

Yes it is right.

mathslover (mathslover):

As : \(\cos \theta = \cfrac{Base}{Hypotenuse} \) And thus : \(\cos R = \cfrac{RS}{RT}\) Since, R = 45 degrees. and cos 45 = \(\cfrac{1}{\sqrt{2}}\) Therefore, \(\cos 45 = \cfrac{RS}{RT}\) \(\implies \cfrac{1}{\sqrt{2}} = \cfrac{26}{RT} \) \(\implies RT = 26\sqrt{2} \)

mathslover (mathslover):

Good work @Jtgovernor

OpenStudy (anonymous):

THANKS :)

OpenStudy (anonymous):

I PROBABLY GOT ANOTHER PROBLEM FOR YOU TO LOOK AT...

mathslover (mathslover):

Sure.

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