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Mathematics 6 Online
OpenStudy (anonymous):

What is the equation of the given circle?

OpenStudy (anonymous):

OpenStudy (anonymous):

A.) (x-3)^2+(y+2)^2=2 B.) (x+3)^2+(y-2)^2=2 C.) (x-3)^2+(y+2)^2=1 D.) (x+3)^2+(y-2)^2=1

OpenStudy (whpalmer4):

can you identify the radius and center of the circle?

OpenStudy (anonymous):

center (-3,2)

OpenStudy (anonymous):

radius = 1?

OpenStudy (whpalmer4):

If you know the circle has radius \(r\) and a center at \((h,k)\), the equation will be \[(x-h)^2+(y-k)^2=r^2\]

OpenStudy (whpalmer4):

let's assume you are correct about the radius, what would the equation be? Then we'll test a point and see if you are right!

OpenStudy (anonymous):

equation would be (x-9)+(y+4)=1

OpenStudy (anonymous):

or B

OpenStudy (anonymous):

i simplified it too much lol

OpenStudy (whpalmer4):

well, no. for one thing, yeah, your "simplification" is "interesting" :-)

OpenStudy (whpalmer4):

Let's do the radius first. you thought the radius was 1, right? if \(r = 1\), what is \(r^2\)?

OpenStudy (anonymous):

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