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Physics 7 Online
OpenStudy (anonymous):

compute the conductivity of a conductor having length of 2 cm and a cross sectional area of 0.06 cm^2 , whose conductance is 3.5*10^3 mhos

OpenStudy (turingtest):

the conductance of a conductor can be thought of like a pipe, and the electricity like water. The wider the pipe is the easier it is to flow through, so conductivity is directly proportional to cross sectional area. The longer, the more difficult for water to flow, and so conductivity is inversly proportional to length. The higher the conductivity, the easier again to flow, so conductance is directly proportional to conductivity as well. You can make a simple equation with this info and solve for conductivity.

OpenStudy (anonymous):

I don't know what formula to use

OpenStudy (turingtest):

interpret what I said. In math proportional to area\[C\propto A\]proportional to conductivity\[C\propto\kappa\]inversly proportional to\[C\propto {1\over L}\]

OpenStudy (turingtest):

combine those three expressoins

OpenStudy (anonymous):

i got 0.8

OpenStudy (anonymous):

is that what you got?

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