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Solve by completing the square: y = x²+7x+12
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You need to first put it in the form of \(-12=x^2+7x\)
Then you will be able to use the steps necessary to complete the square.
but I would have to divide 7 by 2 and square it. how would I do that?
Well, instead of writing 7/2 as 3.5, leave it as a fraction. What's \[\left(\frac72\right)\left(\frac72\right)?\]
Squaring 3.5 seems like a trivial task, but as @KingGeorge pointed out, you do not have to reduce to a decimal, you can leave everything as a fraction while you work the equation.
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\[x^{2} +7x + (\frac{7}{2})^{2} = -12 + (\frac{7}{2})^{2}\] \[x^{2} +7x +\frac{49}{4} = -12 + \frac{49}{4}\]
\[\rightarrow (x+\frac{7}{2})^{2} = \frac{-48+49}{4}\] \[(x+\frac{7}{2})^{2} = \frac{1}{4}\]
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