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Integrate... initial conditions y=0,y(x) x=0,x Solve for y(x) dy/dx = y - x
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can I use separation of variables
Hmmmmm no :( not so much.
I didn't think so
\[\large y'-y=-x\] Looks like we have to start from here, finding the complimentary solution first,\[\large y'-y=0\]
I hate undetermined coefficients... ugh
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XD
Ok, I'm going to attempt it. Thanks I just needed a little discussion about how to get started. I made up this problem, the real thing is a little more involved. Thanks zepdrix
cool c:
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