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Describe the solutions to the quadratic equation below: A. 2 rational roots B. 2 irrational roots C. 1 rational (double) root D. 2 complex roots
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\[\large x^2+6x+9=0\] This particular quadratic factors nicely. Have you been working with factoring? Or are you more familiar with the Quadratic Formula? \[\large x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
not necessarily familiar.
a=1 b=6 c=9 ?
Yes. If we end up with a negative value under the square root, we can immediately determine that we have `2 complex solutions`, because complex solutions always come in pairs.
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