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Mathematics 18 Online
OpenStudy (anonymous):

What is the equation of the graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

x = –1/2(y – 1)2 + 2 x =1/2 (y – 1)2 + 2 y = –1/2(x – 1)2 + 2 y =1/2 (x – 1)2 + 2

OpenStudy (anonymous):

well i know its NOT a .

OpenStudy (anonymous):

Well your graph is concave up. Are there any equations you can eliminate based on that?

OpenStudy (anonymous):

the negative ones ? a &d ?

OpenStudy (anonymous):

or C both face down

OpenStudy (anonymous):

^ Right

OpenStudy (anonymous):

since it opens up, it has to be \(y=...\)

OpenStudy (anonymous):

i meant A& c . sorry.

OpenStudy (anonymous):

Then for A and B you should look at what they would be if you solved for y. That should show you that they also cannot be the answers, since then you would get y=sqrt(stuff).

OpenStudy (anonymous):

wait did we rule out a and c ? right ?

OpenStudy (anonymous):

because their negative.

OpenStudy (anonymous):

Yes. You can also rule out B because it would be the wrong type of equation.

OpenStudy (anonymous):

thank you for all you help (:

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