Choose the equation of the line passing through the point (4, -2) and perpendicular to y = 1/3x - 7. y = -3x - 14 y = 3x - 10 y = -3x + 10 y = 3x + 14
the slope of your line is m = 1/3 so the slope of the perpendicular is -1/m then when you have that use the point slope form y = mx + b and substitute x = 4 and y = -2 to find b
confused :/
ok... so if the slope of you given line is m = 1/3 what is -1/m
1/-3?
not quite... you need the negative reciprocal of 1/3 ...
-3/1?
correct or make it simple the slope of the perpendicular line is -3 so the line looks like y = -3x + b to find b, use the point (4, -2) and substitute x = 4 and y = -2 to get the value of b
ugh what do I do from there?
ok... replace x with 4 and y with -2 so you have \[-2 = -3 \times 4 + b\] you need to calculate the value of b
how do you calculate the value of B?
never mind I got it
ok... you if you simplify the equation above you ge \[-2 = -12 + b\] whats the value of b..?
10
so the equation is y = -3x + 10
yeess :) thanks!
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