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-4x <_ 1/3
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is that <=?
yes
\[-4x \le \frac{ 1 }{ 3 }\]\[x > -\frac{ 1 }{ 12 }\]
\[\large -4x \le\frac13\] divide both sides by -4 and flip the sign (since you're dividing by a negative) \[\large \frac{-4x}{-4} \le \frac{1/3}{-4}\]\[\large x \ge -\frac{1}{12}\]
@Soumyadeep your sign changed magically?
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How do you divide 1/3 by 4 and get 1/12( i know that sound like a stupid question but i suck at fractions)
@Jhannybean u explained it :)
\[\large -\frac{1/3}{4}= -\frac{1}{3}\cdot \frac{1}{4}\]
ok that makes sense, thanks!
\[\frac{\frac{ 1 }{ 3 }}{ 4 }\]\[\frac{ 1 }{ 3 } \div 4\]\[\frac{ 1 }{ 3 } \times \frac{ 1 }{ 4 }\]\[\frac{ 1 }{ 12 }\]
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