Question

Find the product of the complex number and its conjugate.
3 + 3i

Answer 1

Given: 3 + 3i

Conjugate: 3 - 3i

So:

(3 + 3i)(3 - 3i)

Answer 2

If one complex no. is 3+3i then other has to be 3-3i
So their product, that is (3+3i)(3-3i)= (3^2)-((3i)^2)
The square of 3 will be 9
And the square of 3i will be -9 ( as i is square root of -1. So square of i will give us -1 which when multiplied by the square of 3 gives us -9)

So the final answer will be 9-(-9)=18 :)

Answer 3

thank u guys!!

Answer 4

You're Welcome. :)