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Mathematics 13 Online
OpenStudy (anonymous):

In △PQR, QS is an altitude. Solve for x and y.

OpenStudy (anonymous):

OpenStudy (anonymous):

THey didnt give us an example on how to find the altitude

OpenStudy (jhannybean):

create a ratio. \[\large \frac{20}{x}=\frac{x}{5}\] cross multiply. \[\large x^2 =(20)(5)\] solve for x. \[\large x=\sqrt{20 \times 5}\]

OpenStudy (anonymous):

I did that but none of the answers match X

OpenStudy (jhannybean):

What is your value of x?

OpenStudy (anonymous):

Oh I see. I did 25 over 5

OpenStudy (jhannybean):

Yeah. Nope.

OpenStudy (anonymous):

Ok. So then to get Y i use 25 ? And what else?

OpenStudy (jhannybean):

Then to get your y, use pythagorean theorem. \[\large y^2= 20^2 + x^2\] And you have your value for x, just plug it in and solve. \[\large y=\sqrt{20^2+x^2}\]

OpenStudy (anonymous):

ok so I should get 30?

OpenStudy (anonymous):

My bad not 30

OpenStudy (jhannybean):

What was your x-value equal to?

OpenStudy (anonymous):

10 and y = 10 sqrt5

OpenStudy (jhannybean):

Good job.

OpenStudy (anonymous):

ty

OpenStudy (anonymous):

For the help

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