Find the slope-intercept form of this equation... 3x-2y=-4
\[Slope~Intercept~Form\] \[y = mx + b\]
Where: \[m~is~the~slope\] \[b~is~the~y-intercept\]
3x-2y=-4 Solve for y. 3x-2y=-4 *subtract 3x from both sides* 3x-2y=-4 -3x -3x ---- ----- -2y = -3x - 4 *Divide by -2 on both sides* -2y = -3x - 4 ---- --- --- -2 -2 -2 *what do you get?*
Your equation is in standard form \[\large Ax+By = C\] All you need to so is change it to slpe intercept form \[\large y=mx+b\] where b= y-intercept and m = slope.
y= 1.5x +2
\[y = \frac{ 3x }{ 2 } + 2\]
seems right.
\[\large y=\color{blue}{1.5}x+\color{green}3\]\[\large \color{blue}{m=\text{slope}} \ \, \ \color{green}{b= \text{y-intercept}}\]
+3?
ohh +2***
-_- typo.
lol Jhanny
-_-
Sorry!!
ok back to business guys ^_^
lol its okay :)
so what next?
umm... idk.. ur da one with the open question lol
i mean in solving...
what do you mean? You just said: Find the slope-intercept form of this equation... 3x-2y=-4 and we did...
so what is the slope?
Find the slope-intercept form of this equation... 3x-2y=-4 Point Slope Form of 3x-2y=-4 is y = 3/2x + 2 Point slope formula: y = mx + b So: Slope = m = 3/2 y-intercept = b = 2
I stated what the slope was... i just made a typo in typing a 3 instead of a 2 for the y-intercept.... <_<
lol yep... ^ Jhanny did :)
so how would i draw this?
please help @some_someone
well its a line.
do you know how to draw lines?
http://www.algebra.com/algebra/homework/Graphs/Graphing-by-Slope-Intercept-Method.lesson
a line from where to where?
Start at the y-intercept. Y-intercept = 2|dw:1371949835473:dw|
Now we take our slope which was 3/2, and from this point (0,2), we move up 3, and over 2.
|dw:1371950168025:dw|
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