Question

A river flows with a constant E'k' of 4*(10^6) J, whose mg is given as 5*(10^5) N. It falls down from a certain height towards a turbine kept at a lower level to produce electrical energy using the fact that energy produced at any height is given by e=mgh+c(neglecting the loss of energy). Which implies E=7*(10^5)h+2*(10^6).
Another River E=5*(10^5) *h+22*(10^6).
Draw the equation for the two equations in the same graph sheet by taking E and h as y and x resp.Also find the height at which the produce the same amount of energy.

Second Pair.
E=7*(10^5)h+2*(10^6);
E=7*(10*5)h + 6*(10^6).

Answer 1

Third Pair.
E=4*(10^5)h+2*(10^6)
3E=12*(10^5)h+6*(10^6)

I understand the first pair is intersecting, second pair is parallel and third pair is co incident.

Please Help.

Answer 2

you're right, wat do u need help with ?

Answer 3

i coudnt substitute and get values for x and y to plot the graph!! @ganeshie8

Answer 4

ok, pick one pair. il walk u through plotting the graph

Answer 5

E=7*(10^5)h+2*(10^6); E=7*(10*5)h + 6*(10^6).

Answer 6

draw coordinate grid and label x and y

Answer 7

what is the apt scale to be taken?
@ganeshie8

Answer 8

10^6 = 1

Answer 9

x axis?

Answer 10

1 unit = 1 Megajoule

Answer 11

x axis is the height

Answer 12

For what value does x axis take which equals y axis??
I have substituted many values but nothing seems to work

Answer 13

@ganeshie8

Answer 14

didnt get wat u asking

Answer 15

I need points to draw the graph rite??
Like for example let us take two equations x+y=7;x-y=3.
then
Like this how can i find for these two equations so that i can plot the graph?? @ganeshie8

Answer 16

same way

Answer 17

E=7*(10^5)h+2*(10^6);
E=7*(10*5)h + 6*(10^6).

Answer 18

since we have taken 10^6 = 1 unit in y, the equations become :-

E = 0.7h + 2
E = 0.7h + 6

Answer 19

Now plugin and fill the table

Answer 20

Thank You!!