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Can you explain how to factorise 5a+ax-2b+by please
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Put all the lie terms together
Pout all the like terms together
a(5+x) + b(-2+y)
\[\huge 5a+ax-2b+by\] first, seperate this as: \[\huge 5a+ax ~and~-2b+by\] then take common a : \[\huge 5a+ax=a(5+x)\] then take b as common: \[\huge -2b+by=+b(-2+y)\] then combine this: we get, \[\huge a(5+x)+b(-2+y)\] so ^^^^ this is your answer
got it... @Peanut1
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how to factorise 5a+ax-2b+by so for your help let step by step --- if you check it in the first and second term is common factor a .... ...and how have wrote above @mayankdevnani so is understandably sure right easy
thank you... @jhonyy9
yw
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