The position of a particle as it moves along the x axis is given for t0 by x=(t^3 - 3t^2 +6t)m , where t in sec.Where id the particle wen it achieves its minimum speed (after t=0)?

Question

The position of a particle as it moves along the x axis is given for t>0 by  x=(t^3 - 3t^2 +6t)m , where t in sec.Where id the particle wen it achieves its minimum speed (after t=0)?

badhi · Answer

You've already asked a similar question previously. So why don't you tell us this time what you've tried so far with this one...

whpalmer4 · Answer

speed or velocity is just the first derivative of position.  Why not find dx/dt (velocity), find d^2x/dt^2 (acceleration), set acceleration = 0, and solve for t?  Check to see if you've got a local maxima or minima, of course.

whpalmer4 · Answer

Once you have t, you can find the position.