Question

Hello everyone, I am suppose to identify the slope, y-intercept, and then graph the line,
all they gave me was y=4x, anyone have a clue how to solve this?

Answer 1

If the equation is the line is
\[\Large y=mx+b\]
where : m is the slope and b is the y-intercept.

Answer 2

u hv to compare it with the equation\[y=mx+c\]

Answer 3

so the slope is 4?

Answer 4

@violetanna Of course !

Answer 5

and the y intercept is 0?

Answer 6

@violetanna exactly

Answer 7

so the graph would look like

Answer 8

cuz slope= rise/run so it would be 4/1 and I would just go up 4 and over one when graphing the line correct?

Answer 9

@Noura11

Answer 10

You can graph the line in another way by giving two values of x and finding the corresponding values of y like this :
\[\Large\text{The equation of the line is : }y=4x.\\
\\\Large \text{ when }x=0\text{ then } y=4\times 0=0
\\\Large\text{ when } x=1 \text{ then } y=4\times 1=4
\]
So we place the points (0,0) and (1,4) and we trace the line passing these points

Answer 11

but can I graph it as slope=rise/run=4/1

Answer 12

yes And what did you write above is correct. I just gave you another way ;)

Answer 13

ty