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Mathematics 13 Online
OpenStudy (math2400):

Limits...can someone just explain how i go about these kinds of problems? **Posting pic

OpenStudy (math2400):

zepdrix (zepdrix):

The limit definition of the derivative is: \[\large \lim_{h\to0}\frac{f(x+h)-\color{red}{f(x)}}{h}\] \[\large \lim_{h\to0}\frac{(1+h)^6-\color{red}{1}}{h}\] Something to keep in mind, that red 1 is actually 1^6. Let's write it that way. \[\large \lim_{h\to0}\frac{(1+h)^6-\color{red}{1^6}}{h}\]

zepdrix (zepdrix):

It can be a little tricky to recognize what's going on with these sometimes. I wrote it as 1^6 so it matches the form of the definition. We see that our function \(\large f\) is going to be, \(\large f(x)=x^6\) And what do you suppose our c value is? :o

zepdrix (zepdrix):

If our function is \(\large f(x)=x^6\) Then the derivative would be,\[\large \lim_{h\to0}\frac{(x+h)^6-x^6}{h}\]But that's not quite what we have, our function is being evaluated at a particular point.

OpenStudy (math2400):

i believe c would equal 1

zepdrix (zepdrix):

Yay good job c:

OpenStudy (math2400):

thank you so much(:

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