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Mathematics 11 Online
OpenStudy (anonymous):

Did i do this right?

OpenStudy (anonymous):

P=a+b+c ; for A

OpenStudy (anonymous):

i got P-b-c=a

OpenStudy (anonymous):

that is correct

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

But how would i do A=1/2bh;solve for h ?

OpenStudy (anonymous):

@robz8

OpenStudy (anonymous):

\[\frac{ 2A }{ b } = h\] you divide by 1/2 on both sides, then divide by b on both sides

OpenStudy (anonymous):

same thing as adding and subtracting, except you multiply and divide

OpenStudy (anonymous):

oh wow thank you i understand

OpenStudy (anonymous):

you're welcome!

OpenStudy (anonymous):

Sorry for so many questions (i probably have a few more coming) but did i do this right? \[S=2\pi rh+2\pi r ^{2}\] ;solve for h

OpenStudy (anonymous):

[S-2\pi r ^{2}/ 2\pi r = h\]

OpenStudy (anonymous):

\[S-2\pi r ^{2}/2\pi r =h\]

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