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Find the solutions to 0 > –(x – 2)3
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How do I put it into a inequality?
^3
0 > –(x – 2)^3
\[\large 0 > -(x+3)^3\] First, divide both sides by the negative. Dividing or multiplying by a negative implies that you flip your sign \[\large 0 < (x+3)^3\] now take the cube root of both sides. This helps you evaluate you x value without having to expand the function. \[\large \sqrt[3]{0}< \sqrt[3]{(x+3)^3}\] Now simplify \[\large 0 < x+3 \] subtract 3 from both sides \[\large 0-3 < x+3-3\] simplify \[\large x < -3\]
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