Question

Simplify please. [(3a)/(a^2-9a+18)]-[2/(a-6)]

Answer 1

The idea is to make the denominators the same so we can subtract the numerators.

\[\large \frac{3a}{a^2-9a+18} - \frac{2}{a-6}\]


\[\large \frac{3a}{(a-6)(a-3)} - \frac{2}{a-6}\]


\[\large \frac{3a}{(a-6)(a-3)} - \frac{2(a-3)}{(a-6)(a-3)}\]


\[\large \frac{3a}{(a-6)(a-3)} - \frac{2a-6}{(a-6)(a-3)}\]


\[\large \frac{3a-(2a-6)}{(a-6)(a-3)}\]


\[\large \frac{3a-2a+6}{(a-6)(a-3)}\]


\[\large \frac{a+6}{(a-6)(a-3)}\]


\[\large \frac{a+6}{a^2-9a+18}\]

Answer 2

Oh, wow! Thank you so much!

Answer 3

you're welcome