Question

Verify the following identity:
cot(x - pi/2)= -tanx

Answer 1

i have this : tan (–x) = –tan x
cot (pi/2-x)= tan
plug in -x for x.
= (x+pi/2)

Answer 2

but im doing something wrong

Answer 3

\[\cot (x- \frac{ \pi }{ 2 })=\cot(-(\frac{ \pi }{ 2 }-x))=-\cot (\frac{ \pi }{ 2 }-x)=-tanx\]

Answer 4

actually\[\cot (\frac{ \pi }{ 2 }-x)=\tan x\]

Answer 5

because its 1st quadrant

Answer 6

so i do -(pi/2-x)?

Answer 7

u should tell\[\cot(-(\frac{ \pi }{ 2 }-x))\]

Answer 8

\[=-\cot(\frac{ \pi }{ 2 }-x)\]

Answer 9

\[=-\tan x\]

Answer 10

ok thanks!

Answer 11

welcome