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Mathematics 15 Online
OpenStudy (anonymous):

Is this truth table right? The proposition is [ (¬p ∧ q) → ¬r ] ↔ [ r ∧ ¬ ( p ∨ ¬q)]

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

Its correct

OpenStudy (loser66):

how?

ganeshie8 (ganeshie8):

ok the biconditional part is messed up. left and right expressions are correct.

ganeshie8 (ganeshie8):

actually biconditional part is also correct. the whole thing looks perfect to me

ganeshie8 (ganeshie8):

good work @Juarismi , i checked the truthtable from my digital logic background. its perfect ! i dont remember much of propositional logic...

OpenStudy (anonymous):

Nice, thanks

ganeshie8 (ganeshie8):

np :)

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